Base | Representation |
---|---|
bin | 10100101011101100000… |
… | …110011111101010100101 |
3 | 12000212121212022211120021 |
4 | 110223230012133222211 |
5 | 141241310341130341 |
6 | 3004534130435141 |
7 | 204454101332626 |
oct | 24535406375245 |
9 | 5025555284507 |
10 | 1421300333221 |
11 | 4a8851a9196a |
12 | 1ab55a732ab1 |
13 | a4049805342 |
14 | 4cb1149ba4d |
15 | 26e881349d1 |
hex | 14aec19faa5 |
1421300333221 has 2 divisors, whose sum is σ = 1421300333222. Its totient is φ = 1421300333220.
The previous prime is 1421300333197. The next prime is 1421300333231. The reversal of 1421300333221 is 1223330031241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1421090489025 + 209844196 = 1192095^2 + 14486^2 .
It is a cyclic number.
It is not a de Polignac number, because 1421300333221 - 231 = 1419152849573 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1421300333231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710650166610 + 710650166611.
It is an arithmetic number, because the mean of its divisors is an integer number (710650166611).
Almost surely, 21421300333221 is an apocalyptic number.
It is an amenable number.
1421300333221 is a deficient number, since it is larger than the sum of its proper divisors (1).
1421300333221 is an equidigital number, since it uses as much as digits as its factorization.
1421300333221 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1421300333221 its reverse (1223330031241), we get a palindrome (2644630364462).
The spelling of 1421300333221 in words is "one trillion, four hundred twenty-one billion, three hundred million, three hundred thirty-three thousand, two hundred twenty-one".
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