Base | Representation |
---|---|
bin | 1000010001011110100… |
… | …0110111000011100001 |
3 | 111120212022121220021221 |
4 | 2010113220313003201 |
5 | 4312040402224001 |
6 | 145143250015041 |
7 | 13161061245616 |
oct | 2042750670341 |
9 | 446768556257 |
10 | 142130508001 |
11 | 55305a6a359 |
12 | 23667277481 |
13 | 105310a2111 |
14 | 6c4457a50d |
15 | 3a6ccb31a1 |
hex | 2117a370e1 |
142130508001 has 2 divisors, whose sum is σ = 142130508002. Its totient is φ = 142130508000.
The previous prime is 142130507951. The next prime is 142130508019. The reversal of 142130508001 is 100805031241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 123464390625 + 18666117376 = 351375^2 + 136624^2 .
It is a cyclic number.
It is not a de Polignac number, because 142130508001 - 225 = 142096953569 is a prime.
It is not a weakly prime, because it can be changed into another prime (142136508001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71065254000 + 71065254001.
It is an arithmetic number, because the mean of its divisors is an integer number (71065254001).
Almost surely, 2142130508001 is an apocalyptic number.
It is an amenable number.
142130508001 is a deficient number, since it is larger than the sum of its proper divisors (1).
142130508001 is an equidigital number, since it uses as much as digits as its factorization.
142130508001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 960, while the sum is 25.
Adding to 142130508001 its reverse (100805031241), we get a palindrome (242935539242).
The spelling of 142130508001 in words is "one hundred forty-two billion, one hundred thirty million, five hundred eight thousand, one".
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