1421310140431 has 4 divisors (see below), whose sum is σ = 1435109268112. Its totient is φ = 1407511012752.

The previous prime is 1421310140407. The next prime is 1421310140521. The reversal of 1421310140431 is 1340410131241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1421310140431 - 2⁹ = 1421310139919 is a prime.

It is a super-2 number, since 2×1421310140431² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1421310140396 and 1421310140405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1421310143431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6899563686 + ... + 6899563891.

It is an arithmetic number, because the mean of its divisors is an integer number (358777317028).

Almost surely, 2^{1421310140431} is an apocalyptic number.

1421310140431 is a deficient number, since it is larger than the sum of its proper divisors (13799127681).

1421310140431 is a wasteful number, since it uses less digits than its factorization.

1421310140431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13799127680.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1421310140431 its reverse (1340410131241), we get a palindrome (2761720271672).

The spelling of 1421310140431 in words is "one trillion, four hundred twenty-one billion, three hundred ten million, one hundred forty thousand, four hundred thirty-one".