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1421313420103 = 3739299777011
BaseRepresentation
bin10100101011101100111…
…000011010101101000111
312000212122202221201101121
4110223230320122231013
5141241322213420403
63004535315134411
7204454320510043
oct24535470325507
95025582851347
101421313420103
114a8859410275
121ab562ba4407
13a404c437c65
144cb13107023
1526e8936c3bd
hex14aece1ab47

1421313420103 has 8 divisors (see below), whose sum is σ = 1460098972080. Its totient is φ = 1382547430080.

The previous prime is 1421313420097. The next prime is 1421313420133. The reversal of 1421313420103 is 3010243131241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1421313420103 - 225 = 1421279865671 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1421313420133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4743133 + ... + 5033878.

It is an arithmetic number, because the mean of its divisors is an integer number (182512371510).

Almost surely, 21421313420103 is an apocalyptic number.

1421313420103 is a deficient number, since it is larger than the sum of its proper divisors (38785551977).

1421313420103 is an equidigital number, since it uses as much as digits as its factorization.

1421313420103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9780977.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1421313420103 its reverse (3010243131241), we get a palindrome (4431556551344).

The spelling of 1421313420103 in words is "one trillion, four hundred twenty-one billion, three hundred thirteen million, four hundred twenty thousand, one hundred three".

Divisors: 1 37 3929 145373 9777011 361749407 38413876219 1421313420103