Base | Representation |
---|---|
bin | 11010011110010101… |
… | …10011110011101101 |
3 | 1100200112112002122112 |
4 | 31033022303303231 |
5 | 213102030314342 |
6 | 10310204453405 |
7 | 1012133442053 |
oct | 151712636355 |
9 | 40615462575 |
10 | 14213135597 |
11 | 6033a43161 |
12 | 2907b4a265 |
13 | 145681500b |
14 | 98b9181d3 |
15 | 582bd4682 |
hex | 34f2b3ced |
14213135597 has 2 divisors, whose sum is σ = 14213135598. Its totient is φ = 14213135596.
The previous prime is 14213135581. The next prime is 14213135609. The reversal of 14213135597 is 79553131241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9283129801 + 4930005796 = 96349^2 + 70214^2 .
It is a cyclic number.
It is not a de Polignac number, because 14213135597 - 24 = 14213135581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14213135527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106567798 + 7106567799.
It is an arithmetic number, because the mean of its divisors is an integer number (7106567799).
Almost surely, 214213135597 is an apocalyptic number.
It is an amenable number.
14213135597 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213135597 is an equidigital number, since it uses as much as digits as its factorization.
14213135597 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 113400, while the sum is 41.
The spelling of 14213135597 in words is "fourteen billion, two hundred thirteen million, one hundred thirty-five thousand, five hundred ninety-seven".
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