Base | Representation |
---|---|
bin | 1100111011010100000101… |
… | …1011000111011101111111 |
3 | 1212022202121110201211222022 |
4 | 3032311001123013131333 |
5 | 3330332004432104413 |
6 | 50121232311310355 |
7 | 2664602653060421 |
oct | 316650133073577 |
9 | 55282543654868 |
10 | 14213144409983 |
11 | 458a840535632 |
12 | 171672937b3bb |
13 | 7c13a85374bc |
14 | 371cc414a811 |
15 | 199ab32ec608 |
hex | ced416c777f |
14213144409983 has 2 divisors, whose sum is σ = 14213144409984. Its totient is φ = 14213144409982.
The previous prime is 14213144409973. The next prime is 14213144410037. The reversal of 14213144409983 is 38990444131241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14213144409983 - 210 = 14213144408959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14213144409923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106572204991 + 7106572204992.
It is an arithmetic number, because the mean of its divisors is an integer number (7106572204992).
Almost surely, 214213144409983 is an apocalyptic number.
14213144409983 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213144409983 is an equidigital number, since it uses as much as digits as its factorization.
14213144409983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2985984, while the sum is 53.
The spelling of 14213144409983 in words is "fourteen trillion, two hundred thirteen billion, one hundred forty-four million, four hundred nine thousand, nine hundred eighty-three".
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