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14213144410141 is a prime number
BaseRepresentation
bin1100111011010100000101…
…1011000111100000011101
31212022202121110201212012011
43032311001123013200131
53330332004432111031
650121232311311221
72664602653061035
oct316650133074035
955282543655164
1014213144410141
11458a840535766
12171672937b511
137c13a85375b1
14371cc414a8c5
15199ab32ec6b1
hexced416c781d

14213144410141 has 2 divisors, whose sum is σ = 14213144410142. Its totient is φ = 14213144410140.

The previous prime is 14213144410121. The next prime is 14213144410163. The reversal of 14213144410141 is 14101444131241.

14213144410141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12224959809241 + 1988184600900 = 3496421^2 + 1410030^2 .

It is a cyclic number.

It is not a de Polignac number, because 14213144410141 - 211 = 14213144408093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14213144410121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106572205070 + 7106572205071.

It is an arithmetic number, because the mean of its divisors is an integer number (7106572205071).

Almost surely, 214213144410141 is an apocalyptic number.

It is an amenable number.

14213144410141 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213144410141 is an equidigital number, since it uses as much as digits as its factorization.

14213144410141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 31.

Adding to 14213144410141 its reverse (14101444131241), we get a palindrome (28314588541382).

The spelling of 14213144410141 in words is "fourteen trillion, two hundred thirteen billion, one hundred forty-four million, four hundred ten thousand, one hundred forty-one".