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1421321040421 is a prime number
BaseRepresentation
bin10100101011101101010…
…101011111001000100101
312000212200022021212111121
4110223231111133020211
5141241331141243141
63004540150333541
7204454442335522
oct24535525371045
95025608255447
101421321040421
114a8862745557
121ab56565a2b1
13a4050ba5619
144cb1412c149
1526e89d751d1
hex14aed55f225

1421321040421 has 2 divisors, whose sum is σ = 1421321040422. Its totient is φ = 1421321040420.

The previous prime is 1421321040409. The next prime is 1421321040427. The reversal of 1421321040421 is 1240401231241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 738888091396 + 682432949025 = 859586^2 + 826095^2 .

It is a cyclic number.

It is not a de Polignac number, because 1421321040421 - 239 = 871565226533 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1421321040427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710660520210 + 710660520211.

It is an arithmetic number, because the mean of its divisors is an integer number (710660520211).

Almost surely, 21421321040421 is an apocalyptic number.

It is an amenable number.

1421321040421 is a deficient number, since it is larger than the sum of its proper divisors (1).

1421321040421 is an equidigital number, since it uses as much as digits as its factorization.

1421321040421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1421321040421 its reverse (1240401231241), we get a palindrome (2661722271662).

The spelling of 1421321040421 in words is "one trillion, four hundred twenty-one billion, three hundred twenty-one million, forty thousand, four hundred twenty-one".