1421322749857 has 2 divisors, whose sum is σ = 1421322749858. Its totient is φ = 1421322749856.

The previous prime is 1421322749851. The next prime is 1421322749881. The reversal of 1421322749857 is 7589472231241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1255742118801 + 165580631056 = 1120599^2 + 406916^2 .

It is a cyclic number.

It is not a de Polignac number, because 1421322749857 - 2²³ = 1421314361249 is a prime.

It is a super-2 number, since 2×1421322749857² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1421322749798 and 1421322749807.

It is not a weakly prime, because it can be changed into another prime (1421322749851) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710661374928 + 710661374929.

It is an arithmetic number, because the mean of its divisors is an integer number (710661374929).

Almost surely, 2^{1421322749857} is an apocalyptic number.

It is an amenable number.

1421322749857 is a deficient number, since it is larger than the sum of its proper divisors (1).

1421322749857 is an equidigital number, since it uses as much as digits as its factorization.

1421322749857 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6773760, while the sum is 55.

The spelling of 1421322749857 in words is "one trillion, four hundred twenty-one billion, three hundred twenty-two million, seven hundred forty-nine thousand, eight hundred fifty-seven".