Base | Representation |
---|---|
bin | 10100101011101101011… |
… | …100000000011101101111 |
3 | 12000212200102111201100012 |
4 | 110223231130000131233 |
5 | 141241332110443212 |
6 | 3004540251123435 |
7 | 204454463015252 |
oct | 24535534003557 |
9 | 5025612451305 |
10 | 1421322749807 |
11 | 4a8863702874 |
12 | 1ab56614357b |
13 | a40513536ac |
14 | 4cb14455099 |
15 | 26e8a0b1922 |
hex | 14aed70076f |
1421322749807 has 2 divisors, whose sum is σ = 1421322749808. Its totient is φ = 1421322749806.
The previous prime is 1421322749797. The next prime is 1421322749851. The reversal of 1421322749807 is 7089472231241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1421322749807 - 220 = 1421321701231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1421322749857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710661374903 + 710661374904.
It is an arithmetic number, because the mean of its divisors is an integer number (710661374904).
Almost surely, 21421322749807 is an apocalyptic number.
1421322749807 is a deficient number, since it is larger than the sum of its proper divisors (1).
1421322749807 is an equidigital number, since it uses as much as digits as its factorization.
1421322749807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1354752, while the sum is 50.
The spelling of 1421322749807 in words is "one trillion, four hundred twenty-one billion, three hundred twenty-two million, seven hundred forty-nine thousand, eight hundred seven".
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