Base | Representation |
---|---|
bin | 1000010001011111001… |
… | …0011010010001010111 |
3 | 111120212111100002111201 |
4 | 2010113302122101113 |
5 | 4312042022332133 |
6 | 145143415413331 |
7 | 13161121443565 |
oct | 2042762322127 |
9 | 446774302451 |
10 | 142133011543 |
11 | 5530741a2a6 |
12 | 23668084247 |
13 | 1053176a7c3 |
14 | 6c44a2ca35 |
15 | 3a6d109d7d |
hex | 2117c9a457 |
142133011543 has 4 divisors (see below), whose sum is σ = 142158133480. Its totient is φ = 142107889608.
The previous prime is 142133011529. The next prime is 142133011571. The reversal of 142133011543 is 345110331241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 142133011543 - 225 = 142099457111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142133011513) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12552480 + ... + 12563797.
It is an arithmetic number, because the mean of its divisors is an integer number (35539533370).
Almost surely, 2142133011543 is an apocalyptic number.
142133011543 is a deficient number, since it is larger than the sum of its proper divisors (25121937).
142133011543 is an equidigital number, since it uses as much as digits as its factorization.
142133011543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25121936.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 142133011543 its reverse (345110331241), we get a palindrome (487243342784).
The spelling of 142133011543 in words is "one hundred forty-two billion, one hundred thirty-three million, eleven thousand, five hundred forty-three".
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