Base | Representation |
---|---|
bin | 1100111011010100110010… |
… | …1110111010010110001101 |
3 | 1212022210002200202120021112 |
4 | 3032311030232322112031 |
5 | 3330332402020222433 |
6 | 50121303210141405 |
7 | 2664610445606054 |
oct | 316651456722615 |
9 | 55283080676245 |
10 | 14213334148493 |
11 | 458a928649a17 |
12 | 1716780a21865 |
13 | 7c140893abcc |
14 | 371d0141b39b |
15 | 199ac4ccb348 |
hex | ced4cbba58d |
14213334148493 has 2 divisors, whose sum is σ = 14213334148494. Its totient is φ = 14213334148492.
The previous prime is 14213334148487. The next prime is 14213334148501. The reversal of 14213334148493 is 39484143331241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13752920331049 + 460413817444 = 3708493^2 + 678538^2 .
It is a cyclic number.
It is not a de Polignac number, because 14213334148493 - 210 = 14213334147469 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14213334168493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106667074246 + 7106667074247.
It is an arithmetic number, because the mean of its divisors is an integer number (7106667074247).
Almost surely, 214213334148493 is an apocalyptic number.
It is an amenable number.
14213334148493 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213334148493 is an equidigital number, since it uses as much as digits as its factorization.
14213334148493 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2985984, while the sum is 50.
The spelling of 14213334148493 in words is "fourteen trillion, two hundred thirteen billion, three hundred thirty-four million, one hundred forty-eight thousand, four hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •