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14213402141201 is a prime number
BaseRepresentation
bin1100111011010101000011…
…0010010010001000010001
31212022210021102200221201222
43032311100302102020101
53330333021422004301
650121314035334425
72664612232542404
oct316652062221021
955283242627658
1014213402141201
11458a962a6993a
12171679b751415
137c1419a55b93
14371d0a479d3b
15199acac5c31b
hexced50c92211

14213402141201 has 2 divisors, whose sum is σ = 14213402141202. Its totient is φ = 14213402141200.

The previous prime is 14213402141161. The next prime is 14213402141203. The reversal of 14213402141201 is 10214120431241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13874142489601 + 339259651600 = 3724801^2 + 582460^2 .

It is a cyclic number.

It is not a de Polignac number, because 14213402141201 - 230 = 14212328399377 is a prime.

Together with 14213402141203, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14213402141203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106701070600 + 7106701070601.

It is an arithmetic number, because the mean of its divisors is an integer number (7106701070601).

Almost surely, 214213402141201 is an apocalyptic number.

It is an amenable number.

14213402141201 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213402141201 is an equidigital number, since it uses as much as digits as its factorization.

14213402141201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 14213402141201 its reverse (10214120431241), we get a palindrome (24427522572442).

The spelling of 14213402141201 in words is "fourteen trillion, two hundred thirteen billion, four hundred two million, one hundred forty-one thousand, two hundred one".