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142134100233 = 347378033411
BaseRepresentation
bin1000010001011111011…
…0100100000100001001
3111120212120101101220120
42010113312210010021
54312042312201413
6145143455013453
713161133626606
oct2042766440411
9446776341816
10142134100233
1155307aa3244
122366850a289
1310531a5c1b8
146c44c336ad
153a6d272723
hex2117da4109

142134100233 has 4 divisors (see below), whose sum is σ = 189512133648. Its totient is φ = 94756066820.

The previous prime is 142134100231. The next prime is 142134100243. The reversal of 142134100233 is 332001431241.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142134100233 - 21 = 142134100231 is a prime.

It is not an unprimeable number, because it can be changed into a prime (142134100231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23689016703 + ... + 23689016708.

It is an arithmetic number, because the mean of its divisors is an integer number (47378033412).

Almost surely, 2142134100233 is an apocalyptic number.

It is an amenable number.

142134100233 is a deficient number, since it is larger than the sum of its proper divisors (47378033415).

142134100233 is an equidigital number, since it uses as much as digits as its factorization.

142134100233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47378033414.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 142134100233 its reverse (332001431241), we get a palindrome (474135531474).

The spelling of 142134100233 in words is "one hundred forty-two billion, one hundred thirty-four million, one hundred thousand, two hundred thirty-three".

Divisors: 1 3 47378033411 142134100233