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14213411000251 is a prime number
BaseRepresentation
bin1100111011010101000101…
…0100000100111110111011
31212022210022001101001001221
43032311101110010332323
53330333031204002001
650121314553252511
72664612401050501
oct316652124047673
955283261331057
1014213411000251
11458a967a6a871
1217167a2704137
137c141b838318
14371d0b704671
15199acb90c1a1
hexced51504fbb

14213411000251 has 2 divisors, whose sum is σ = 14213411000252. Its totient is φ = 14213411000250.

The previous prime is 14213411000227. The next prime is 14213411000263. The reversal of 14213411000251 is 15200011431241.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14213411000251 - 25 = 14213411000219 is a prime.

It is a super-2 number, since 2×142134110002512 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14213411000351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106705500125 + 7106705500126.

It is an arithmetic number, because the mean of its divisors is an integer number (7106705500126).

Almost surely, 214213411000251 is an apocalyptic number.

14213411000251 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213411000251 is an equidigital number, since it uses as much as digits as its factorization.

14213411000251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 25.

Adding to 14213411000251 its reverse (15200011431241), we get a palindrome (29413422431492).

The spelling of 14213411000251 in words is "fourteen trillion, two hundred thirteen billion, four hundred eleven million, two hundred fifty-one", and thus it is an aban number.