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14213411057 is a prime number
BaseRepresentation
bin11010011110010111…
…10111000011110001
31100200120001002111202
431033023313003301
5213102113123212
610310214420545
71012136000126
oct151713670361
940616032452
1014213411057
11603411110a
122908061755
1314568b0501
1498b98a74d
15582c3b0c2
hex34f2f70f1

14213411057 has 2 divisors, whose sum is σ = 14213411058. Its totient is φ = 14213411056.

The previous prime is 14213411041. The next prime is 14213411059. The reversal of 14213411057 is 75011431241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13480138816 + 733272241 = 116104^2 + 27079^2 .

It is a cyclic number.

It is not a de Polignac number, because 14213411057 - 24 = 14213411041 is a prime.

Together with 14213411059, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14213411059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106705528 + 7106705529.

It is an arithmetic number, because the mean of its divisors is an integer number (7106705529).

Almost surely, 214213411057 is an apocalyptic number.

It is an amenable number.

14213411057 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213411057 is an equidigital number, since it uses as much as digits as its factorization.

14213411057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3360, while the sum is 29.

Adding to 14213411057 its reverse (75011431241), we get a palindrome (89224842298).

The spelling of 14213411057 in words is "fourteen billion, two hundred thirteen million, four hundred eleven thousand, fifty-seven".