Base | Representation |
---|---|
bin | 11010011110010111… |
… | …11001010000000001 |
3 | 1100200120001112211012 |
4 | 31033023321100001 |
5 | 213102113420113 |
6 | 10310214530305 |
7 | 1012136035241 |
oct | 151713712001 |
9 | 40616045735 |
10 | 14213420033 |
11 | 603411792a |
12 | 2908066995 |
13 | 14568b4617 |
14 | 98b98db21 |
15 | 582c3daa8 |
hex | 34f2f9401 |
14213420033 has 2 divisors, whose sum is σ = 14213420034. Its totient is φ = 14213420032.
The previous prime is 14213419949. The next prime is 14213420047. The reversal of 14213420033 is 33002431241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11129617009 + 3083803024 = 105497^2 + 55532^2 .
It is a cyclic number.
It is not a de Polignac number, because 14213420033 - 228 = 13944984577 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14213419990 and 14213420008.
It is not a weakly prime, because it can be changed into another prime (14213420083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106710016 + 7106710017.
It is an arithmetic number, because the mean of its divisors is an integer number (7106710017).
Almost surely, 214213420033 is an apocalyptic number.
It is an amenable number.
14213420033 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213420033 is an equidigital number, since it uses as much as digits as its factorization.
14213420033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 14213420033 its reverse (33002431241), we get a palindrome (47215851274).
The spelling of 14213420033 in words is "fourteen billion, two hundred thirteen million, four hundred twenty thousand, thirty-three".
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