Base | Representation |
---|---|
bin | 1100111011010101000111… |
… | …1110100010011101110011 |
3 | 1212022210022211022112200002 |
4 | 3032311101332202131303 |
5 | 3330333042031143214 |
6 | 50121320032020215 |
7 | 2664612564500024 |
oct | 316652176423563 |
9 | 55283284275602 |
10 | 14213422131059 |
11 | 458a973282588 |
12 | 17167a639166b |
13 | 7c1420c347b8 |
14 | 371d0cda0c4b |
15 | 199acc8aa1de |
hex | ced51fa2773 |
14213422131059 has 2 divisors, whose sum is σ = 14213422131060. Its totient is φ = 14213422131058.
The previous prime is 14213422131031. The next prime is 14213422131061. The reversal of 14213422131059 is 95013122431241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14213422131059 - 216 = 14213422065523 is a prime.
It is a super-2 number, since 2×142134221310592 (a number of 27 digits) contains 22 as substring.
Together with 14213422131061, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14213422131079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106711065529 + 7106711065530.
It is an arithmetic number, because the mean of its divisors is an integer number (7106711065530).
Almost surely, 214213422131059 is an apocalyptic number.
14213422131059 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213422131059 is an equidigital number, since it uses as much as digits as its factorization.
14213422131059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 38.
The spelling of 14213422131059 in words is "fourteen trillion, two hundred thirteen billion, four hundred twenty-two million, one hundred thirty-one thousand, fifty-nine".
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