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1421343521329 is a prime number
BaseRepresentation
bin10100101011101110101…
…011001111101000110001
312000212201212121000111211
4110223232223033220301
5141241402420140304
63004542312240121
7204455134406524
oct24535653175061
95025655530454
101421343521329
114a88743aa816
121ab5710a0041
13a4055747034
144cb17100bbb
1526e8bd16204
hex14aeeacfa31

1421343521329 has 2 divisors, whose sum is σ = 1421343521330. Its totient is φ = 1421343521328.

The previous prime is 1421343521303. The next prime is 1421343521359. The reversal of 1421343521329 is 9231253431241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1371369813025 + 49973708304 = 1171055^2 + 223548^2 .

It is an emirp because it is prime and its reverse (9231253431241) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1421343521329 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1421343521291 and 1421343521300.

It is not a weakly prime, because it can be changed into another prime (1421343521359) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710671760664 + 710671760665.

It is an arithmetic number, because the mean of its divisors is an integer number (710671760665).

Almost surely, 21421343521329 is an apocalyptic number.

It is an amenable number.

1421343521329 is a deficient number, since it is larger than the sum of its proper divisors (1).

1421343521329 is an equidigital number, since it uses as much as digits as its factorization.

1421343521329 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 155520, while the sum is 40.

The spelling of 1421343521329 in words is "one trillion, four hundred twenty-one billion, three hundred forty-three million, five hundred twenty-one thousand, three hundred twenty-nine".