Base | Representation |
---|---|
bin | 10100101011101111001… |
… | …000001000011010110101 |
3 | 12000212202101211202011221 |
4 | 110223233020020122311 |
5 | 141241411340001231 |
6 | 3004543142430341 |
7 | 204455255646232 |
oct | 24535710103265 |
9 | 5025671752157 |
10 | 1421351093941 |
11 | 4a8878702179 |
12 | 1ab5737323b1 |
13 | a4057198a7c |
14 | 4cb18112789 |
15 | 26e8c80ed11 |
hex | 14aef2086b5 |
1421351093941 has 2 divisors, whose sum is σ = 1421351093942. Its totient is φ = 1421351093940.
The previous prime is 1421351093933. The next prime is 1421351093969. The reversal of 1421351093941 is 1493901531241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1096512651025 + 324838442916 = 1047145^2 + 569946^2 .
It is a cyclic number.
It is not a de Polignac number, because 1421351093941 - 23 = 1421351093933 is a prime.
It is a super-2 number, since 2×14213510939412 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1421351093741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710675546970 + 710675546971.
It is an arithmetic number, because the mean of its divisors is an integer number (710675546971).
Almost surely, 21421351093941 is an apocalyptic number.
It is an amenable number.
1421351093941 is a deficient number, since it is larger than the sum of its proper divisors (1).
1421351093941 is an equidigital number, since it uses as much as digits as its factorization.
1421351093941 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116640, while the sum is 43.
The spelling of 1421351093941 in words is "one trillion, four hundred twenty-one billion, three hundred fifty-one million, ninety-three thousand, nine hundred forty-one".
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