1421351124703 has 4 divisors (see below), whose sum is σ = 1423849106160. Its totient is φ = 1418853143248.

The previous prime is 1421351124671. The next prime is 1421351124719. The reversal of 1421351124703 is 3074211531241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1421351124703 - 2⁵ = 1421351124671 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1421351124503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1248989875 + ... + 1248991012.

It is an arithmetic number, because the mean of its divisors is an integer number (355962276540).

Almost surely, 2^{1421351124703} is an apocalyptic number.

1421351124703 is a deficient number, since it is larger than the sum of its proper divisors (2497981457).

1421351124703 is an equidigital number, since it uses as much as digits as its factorization.

1421351124703 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2497981456.

The product of its (nonzero) digits is 20160, while the sum is 34.

Adding to 1421351124703 its reverse (3074211531241), we get a palindrome (4495562655944).

The spelling of 1421351124703 in words is "one trillion, four hundred twenty-one billion, three hundred fifty-one million, one hundred twenty-four thousand, seven hundred three".