1421351124737 has 2 divisors, whose sum is σ = 1421351124738. Its totient is φ = 1421351124736.

The previous prime is 1421351124719. The next prime is 1421351124797. The reversal of 1421351124737 is 7374211531241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 969439129201 + 451911995536 = 984601^2 + 672244^2 .

It is an emirp because it is prime and its reverse (7374211531241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1421351124737 - 2¹⁶ = 1421351059201 is a prime.

It is a super-2 number, since 2×1421351124737² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1421351124694 and 1421351124703.

It is not a weakly prime, because it can be changed into another prime (1421351124797) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710675562368 + 710675562369.

It is an arithmetic number, because the mean of its divisors is an integer number (710675562369).

Almost surely, 2^{1421351124737} is an apocalyptic number.

It is an amenable number.

1421351124737 is a deficient number, since it is larger than the sum of its proper divisors (1).

1421351124737 is an equidigital number, since it uses as much as digits as its factorization.

1421351124737 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 141120, while the sum is 41.

Adding to 1421351124737 its reverse (7374211531241), we get a palindrome (8795562655978).

The spelling of 1421351124737 in words is "one trillion, four hundred twenty-one billion, three hundred fifty-one million, one hundred twenty-four thousand, seven hundred thirty-seven".