1421351126737 has 2 divisors, whose sum is σ = 1421351126738. Its totient is φ = 1421351126736.

The previous prime is 1421351126681. The next prime is 1421351126759. The reversal of 1421351126737 is 7376211531241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 793954063681 + 627397063056 = 891041^2 + 792084^2 .

It is a cyclic number.

It is not a de Polignac number, because 1421351126737 - 2¹⁵ = 1421351093969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1421351126693 and 1421351126702.

It is not a weakly prime, because it can be changed into another prime (1421351124737) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710675563368 + 710675563369.

It is an arithmetic number, because the mean of its divisors is an integer number (710675563369).

Almost surely, 2^{1421351126737} is an apocalyptic number.

It is an amenable number.

1421351126737 is a deficient number, since it is larger than the sum of its proper divisors (1).

1421351126737 is an equidigital number, since it uses as much as digits as its factorization.

1421351126737 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 211680, while the sum is 43.

Adding to 1421351126737 its reverse (7376211531241), we get a palindrome (8797562657978).

The spelling of 1421351126737 in words is "one trillion, four hundred twenty-one billion, three hundred fifty-one million, one hundred twenty-six thousand, seven hundred thirty-seven".