Base | Representation |
---|---|
bin | 10100101011101111001… |
… | …000010000011100010111 |
3 | 12000212202101220102021012 |
4 | 110223233020100130113 |
5 | 141241411342024212 |
6 | 3004543143242435 |
7 | 204455256144113 |
oct | 24535710203427 |
9 | 5025671812235 |
10 | 1421351126807 |
11 | 4a8878724937 |
12 | 1ab57374941b |
13 | a40571aaa11 |
14 | 4cb18120743 |
15 | 26e8c819922 |
hex | 14aef210717 |
1421351126807 has 2 divisors, whose sum is σ = 1421351126808. Its totient is φ = 1421351126806.
The previous prime is 1421351126759. The next prime is 1421351126831. The reversal of 1421351126807 is 7086211531241.
It is a strong prime.
It is an emirp because it is prime and its reverse (7086211531241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1421351126807 - 210 = 1421351125783 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1421351126407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710675563403 + 710675563404.
It is an arithmetic number, because the mean of its divisors is an integer number (710675563404).
Almost surely, 21421351126807 is an apocalyptic number.
1421351126807 is a deficient number, since it is larger than the sum of its proper divisors (1).
1421351126807 is an equidigital number, since it uses as much as digits as its factorization.
1421351126807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 41.
The spelling of 1421351126807 in words is "one trillion, four hundred twenty-one billion, three hundred fifty-one million, one hundred twenty-six thousand, eight hundred seven".
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