Base | Representation |
---|---|
bin | 1100111011010111101100… |
… | …0111011010101100111011 |
3 | 1212022212002221000222221211 |
4 | 3032311323013122230323 |
5 | 3330341000223340121 |
6 | 50121512325143551 |
7 | 2664635645155366 |
oct | 316657307325473 |
9 | 55285087028854 |
10 | 14214112324411 |
11 | 459019793400a |
12 | 171695955abb7 |
13 | 7c1500c1c32c |
14 | 371d769050dd |
15 | 199b1d291ce1 |
hex | ced7b1dab3b |
14214112324411 has 4 divisors (see below), whose sum is σ = 14962223499400. Its totient is φ = 13466001149424.
The previous prime is 14214112324403. The next prime is 14214112324417. The reversal of 14214112324411 is 11442321141241.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14214112324411 - 23 = 14214112324403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14214112324417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 374055587466 + ... + 374055587503.
It is an arithmetic number, because the mean of its divisors is an integer number (3740555874850).
Almost surely, 214214112324411 is an apocalyptic number.
14214112324411 is a deficient number, since it is larger than the sum of its proper divisors (748111174989).
14214112324411 is an equidigital number, since it uses as much as digits as its factorization.
14214112324411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 748111174988.
The product of its digits is 6144, while the sum is 31.
Adding to 14214112324411 its reverse (11442321141241), we get a palindrome (25656433465652).
The spelling of 14214112324411 in words is "fourteen trillion, two hundred fourteen billion, one hundred twelve million, three hundred twenty-four thousand, four hundred eleven".
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