Base | Representation |
---|---|
bin | 1100111011010111101111… |
… | …0101001011010100101011 |
3 | 1212022212010202121102212111 |
4 | 3032311323311023110223 |
5 | 3330341011311220133 |
6 | 50121513434223151 |
7 | 2664636152136154 |
oct | 316657365132453 |
9 | 55285122542774 |
10 | 14214124320043 |
11 | 45901a368755a |
12 | 1716961584ab7 |
13 | 7c150355c33b |
14 | 371d7834892b |
15 | 199b1e3611cd |
hex | ced7bd4b52b |
14214124320043 has 4 divisors (see below), whose sum is σ = 14214454639920. Its totient is φ = 14213794000168.
The previous prime is 14214124320029. The next prime is 14214124320091. The reversal of 14214124320043 is 34002342141241.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14214124320043 - 233 = 14205534385451 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14214124319987 and 14214124320014.
It is not an unprimeable number, because it can be changed into a prime (14214124320343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165095383 + ... + 165181456.
It is an arithmetic number, because the mean of its divisors is an integer number (3553613659980).
Almost surely, 214214124320043 is an apocalyptic number.
14214124320043 is a deficient number, since it is larger than the sum of its proper divisors (330319877).
14214124320043 is an equidigital number, since it uses as much as digits as its factorization.
14214124320043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 330319876.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 14214124320043 its reverse (34002342141241), we get a palindrome (48216466461284).
The spelling of 14214124320043 in words is "fourteen trillion, two hundred fourteen billion, one hundred twenty-four million, three hundred twenty thousand, forty-three".
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