Base | Representation |
---|---|
bin | 1000010001100001001… |
… | …0000101000010110011 |
3 | 111120220001221212020121 |
4 | 2010120102011002303 |
5 | 4312101134010303 |
6 | 145144313351111 |
7 | 13161252140641 |
oct | 2043022050263 |
9 | 446801855217 |
10 | 142141313203 |
11 | 5531107a47a |
12 | 2366aa08497 |
13 | 105333b6326 |
14 | 6c45b90191 |
15 | 3a6dbe99bd |
hex | 21184850b3 |
142141313203 has 4 divisors (see below), whose sum is σ = 142252102728. Its totient is φ = 142030523680.
The previous prime is 142141313183. The next prime is 142141313207. The reversal of 142141313203 is 302313141241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 142141313203 - 213 = 142141305011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (142141313207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55392838 + ... + 55395403.
It is an arithmetic number, because the mean of its divisors is an integer number (35563025682).
Almost surely, 2142141313203 is an apocalyptic number.
142141313203 is a deficient number, since it is larger than the sum of its proper divisors (110789525).
142141313203 is a wasteful number, since it uses less digits than its factorization.
142141313203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 110789524.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 142141313203 its reverse (302313141241), we get a palindrome (444454454444).
The spelling of 142141313203 in words is "one hundred forty-two billion, one hundred forty-one million, three hundred thirteen thousand, two hundred three".
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