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1421432433103 = 7502918945107
BaseRepresentation
bin10100101011110011111…
…110011010100111001111
312000212222001220012112111
4110223303332122213033
5141242043200324403
63004555210044451
7204460264220524
oct24536376324717
95025861805474
101421432433103
114a890a608521
121ab596a19727
13a406aca7857
144cb24c4714b
1526e94a2a56d
hex14af3f9a9cf

1421432433103 has 4 divisors (see below), whose sum is σ = 1421451453240. Its totient is φ = 1421413412968.

The previous prime is 1421432433089. The next prime is 1421432433121. The reversal of 1421432433103 is 3013342341241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1421432433103 - 233 = 1412842498511 is a prime.

It is a super-2 number, since 2×14214324331032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1421432403103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9397525 + ... + 9547582.

It is an arithmetic number, because the mean of its divisors is an integer number (355362863310).

Almost surely, 21421432433103 is an apocalyptic number.

1421432433103 is a deficient number, since it is larger than the sum of its proper divisors (19020137).

1421432433103 is an equidigital number, since it uses as much as digits as its factorization.

1421432433103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19020136.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1421432433103 its reverse (3013342341241), we get a palindrome (4434774774344).

The spelling of 1421432433103 in words is "one trillion, four hundred twenty-one billion, four hundred thirty-two million, four hundred thirty-three thousand, one hundred three".

Divisors: 1 75029 18945107 1421432433103