Base | Representation |
---|---|
bin | 10100101011110100011… |
… | …100000110001111111011 |
3 | 12000212222121112111221021 |
4 | 110223310130012033323 |
5 | 141242102143322021 |
6 | 3005000044523311 |
7 | 204460420315426 |
oct | 24536434061773 |
9 | 5025877474837 |
10 | 1421440214011 |
11 | 4a8913a42424 |
12 | 1ab599550537 |
13 | a406c7a033c |
14 | 4cb25cb09bd |
15 | 26e95565c41 |
hex | 14af47063fb |
1421440214011 has 2 divisors, whose sum is σ = 1421440214012. Its totient is φ = 1421440214010.
The previous prime is 1421440213933. The next prime is 1421440214021. The reversal of 1421440214011 is 1104120441241.
It is a strong prime.
It is an emirp because it is prime and its reverse (1104120441241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1421440214011 - 211 = 1421440211963 is a prime.
It is not a weakly prime, because it can be changed into another prime (1421440214021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710720107005 + 710720107006.
It is an arithmetic number, because the mean of its divisors is an integer number (710720107006).
Almost surely, 21421440214011 is an apocalyptic number.
1421440214011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1421440214011 is an equidigital number, since it uses as much as digits as its factorization.
1421440214011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1024, while the sum is 25.
Adding to 1421440214011 its reverse (1104120441241), we get a palindrome (2525560655252).
The spelling of 1421440214011 in words is "one trillion, four hundred twenty-one billion, four hundred forty million, two hundred fourteen thousand, eleven".
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