Base | Representation |
---|---|
bin | 1100111011011011100001… |
… | …1101001001100011111111 |
3 | 1212022221202122111001120002 |
4 | 3032312320131021203333 |
5 | 3330400102201302201 |
6 | 50122202410344515 |
7 | 2665003312345634 |
oct | 316667035114377 |
9 | 55287678431502 |
10 | 14215141431551 |
11 | 4590675828485 |
12 | 1716ba612b13b |
13 | 7c16361aac78 |
14 | 37203346c18b |
15 | 199b7d7c276b |
hex | cedb87498ff |
14215141431551 has 4 divisors (see below), whose sum is σ = 14258087478504. Its totient is φ = 14172195384600.
The previous prime is 14215141431527. The next prime is 14215141431553. The reversal of 14215141431551 is 15513414151241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14215141431551 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14215141431553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21473022980 + ... + 21473023641.
It is an arithmetic number, because the mean of its divisors is an integer number (3564521869626).
Almost surely, 214215141431551 is an apocalyptic number.
14215141431551 is a deficient number, since it is larger than the sum of its proper divisors (42946046953).
14215141431551 is an equidigital number, since it uses as much as digits as its factorization.
14215141431551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42946046952.
The product of its digits is 48000, while the sum is 38.
Adding to 14215141431551 its reverse (15513414151241), we get a palindrome (29728555582792).
The spelling of 14215141431551 in words is "fourteen trillion, two hundred fifteen billion, one hundred forty-one million, four hundred thirty-one thousand, five hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •