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14215144033 is a prime number
BaseRepresentation
bin11010011110100100…
…11110001001100001
31100200200022010201001
431033102132021201
5213103034102113
610310315512001
71012156505416
oct151722361141
940620263631
1014215144033
116035095122
122908758601
13145706923c
1498bcbc10d
15582e7e7dd
hex34f49e261

14215144033 has 2 divisors, whose sum is σ = 14215144034. Its totient is φ = 14215144032.

The previous prime is 14215144007. The next prime is 14215144067. The reversal of 14215144033 is 33044151241.

14215144033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12085044624 + 2130099409 = 109932^2 + 46153^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14215144033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14215143992 and 14215144010.

It is not a weakly prime, because it can be changed into another prime (14215144003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7107572016 + 7107572017.

It is an arithmetic number, because the mean of its divisors is an integer number (7107572017).

Almost surely, 214215144033 is an apocalyptic number.

It is an amenable number.

14215144033 is a deficient number, since it is larger than the sum of its proper divisors (1).

14215144033 is an equidigital number, since it uses as much as digits as its factorization.

14215144033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 14215144033 its reverse (33044151241), we get a palindrome (47259295274).

The spelling of 14215144033 in words is "fourteen billion, two hundred fifteen million, one hundred forty-four thousand, thirty-three".