Base | Representation |
---|---|
bin | 1000010001100011110… |
… | …0011001000110011011 |
3 | 111120220211211101212211 |
4 | 2010120330121012123 |
5 | 4312112003433103 |
6 | 145145351215551 |
7 | 13161445336501 |
oct | 2043074310633 |
9 | 446824741784 |
10 | 142152405403 |
11 | 55317366188 |
12 | 236726775b7 |
13 | 1053579b068 |
14 | 6c4743a671 |
15 | 3a6eb8b36d |
hex | 2118f1919b |
142152405403 has 2 divisors, whose sum is σ = 142152405404. Its totient is φ = 142152405402.
The previous prime is 142152405341. The next prime is 142152405427. The reversal of 142152405403 is 304504251241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142152405403 - 229 = 141615534491 is a prime.
It is not a weakly prime, because it can be changed into another prime (142152405803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71076202701 + 71076202702.
It is an arithmetic number, because the mean of its divisors is an integer number (71076202702).
Almost surely, 2142152405403 is an apocalyptic number.
142152405403 is a deficient number, since it is larger than the sum of its proper divisors (1).
142152405403 is an equidigital number, since it uses as much as digits as its factorization.
142152405403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 142152405403 its reverse (304504251241), we get a palindrome (446656656644).
The spelling of 142152405403 in words is "one hundred forty-two billion, one hundred fifty-two million, four hundred five thousand, four hundred three".
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