Base | Representation |
---|---|
bin | 10100101011111010100… |
… | …111011000011100110111 |
3 | 12000220020211112000211020 |
4 | 110223322213120130313 |
5 | 141242310210213242 |
6 | 3005014225512223 |
7 | 204463116142641 |
oct | 24537247303467 |
9 | 5026224460736 |
10 | 1421543835447 |
11 | 4a896748777a |
12 | 1ab6081a2673 |
13 | a40880b12b8 |
14 | 4cb35965891 |
15 | 26e9e6d36ec |
hex | 14afa9d8737 |
1421543835447 has 4 divisors (see below), whose sum is σ = 1895391780600. Its totient is φ = 947695890296.
The previous prime is 1421543835427. The next prime is 1421543835461. The reversal of 1421543835447 is 7445383451241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1421543835447 - 216 = 1421543769911 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1421543835447.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1421543835427) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236923972572 + ... + 236923972577.
It is an arithmetic number, because the mean of its divisors is an integer number (473847945150).
Almost surely, 21421543835447 is an apocalyptic number.
1421543835447 is a deficient number, since it is larger than the sum of its proper divisors (473847945153).
1421543835447 is an equidigital number, since it uses as much as digits as its factorization.
1421543835447 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 473847945152.
The product of its digits is 6451200, while the sum is 51.
The spelling of 1421543835447 in words is "one trillion, four hundred twenty-one billion, five hundred forty-three million, eight hundred thirty-five thousand, four hundred forty-seven".
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