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1421544433 is a prime number
BaseRepresentation
bin101010010111011…
…0000101111110001
310200001212221100211
41110232300233301
510402403410213
6353020344121
750140633261
oct12456605761
93601787324
101421544433
1166a474411
123380a5041
13198682b6a
14d6b1d7a1
1584bed53d
hex54bb0bf1

1421544433 has 2 divisors, whose sum is σ = 1421544434. Its totient is φ = 1421544432.

The previous prime is 1421544389. The next prime is 1421544461. The reversal of 1421544433 is 3344451241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1421516209 + 28224 = 37703^2 + 168^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1421544433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1421544395 and 1421544404.

It is not a weakly prime, because it can be changed into another prime (1421544473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710772216 + 710772217.

It is an arithmetic number, because the mean of its divisors is an integer number (710772217).

Almost surely, 21421544433 is an apocalyptic number.

It is an amenable number.

1421544433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1421544433 is an equidigital number, since it uses as much as digits as its factorization.

1421544433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 23040, while the sum is 31.

The square root of 1421544433 is about 37703.3742919649. The cubic root of 1421544433 is about 1124.3982119415.

Adding to 1421544433 its reverse (3344451241), we get a palindrome (4765995674).

The spelling of 1421544433 in words is "one billion, four hundred twenty-one million, five hundred forty-four thousand, four hundred thirty-three".