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142171530655741 is a prime number
BaseRepresentation
bin100000010100110111100011…
…100101001111011111111101
3200122101110120102021112121221
4200110313203211033133331
5122113314243321440431
61222212411033153341
741642361031226356
oct4024674345173775
9618343512245557
10142171530655741
1141333675718544
1213b41965b5b851
1361439440656b2
1427171d2c16d2d
15116831b3b7111
hex814de394f7fd

142171530655741 has 2 divisors, whose sum is σ = 142171530655742. Its totient is φ = 142171530655740.

The previous prime is 142171530655727. The next prime is 142171530655769. The reversal of 142171530655741 is 147556035171241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94884645765625 + 47286884890116 = 9740875^2 + 6876546^2 .

It is a cyclic number.

It is not a de Polignac number, because 142171530655741 - 25 = 142171530655709 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142171530655711) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71085765327870 + 71085765327871.

It is an arithmetic number, because the mean of its divisors is an integer number (71085765327871).

Almost surely, 2142171530655741 is an apocalyptic number.

It is an amenable number.

142171530655741 is a deficient number, since it is larger than the sum of its proper divisors (1).

142171530655741 is an equidigital number, since it uses as much as digits as its factorization.

142171530655741 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3528000, while the sum is 52.

The spelling of 142171530655741 in words is "one hundred forty-two trillion, one hundred seventy-one billion, five hundred thirty million, six hundred fifty-five thousand, seven hundred forty-one".