142171530656073 has 4 divisors (see below), whose sum is σ = 189562040874768. Its totient is φ = 94781020437380.

The previous prime is 142171530656059. The next prime is 142171530656081. The reversal of 142171530656073 is 370656035171241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142171530656073 - 2⁵ = 142171530656041 is a prime.

It is not an unprimeable number, because it can be changed into a prime (142171530656083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23695255109343 + ... + 23695255109348.

It is an arithmetic number, because the mean of its divisors is an integer number (47390510218692).

Almost surely, 2^{142171530656073} is an apocalyptic number.

It is an amenable number.

142171530656073 is a deficient number, since it is larger than the sum of its proper divisors (47390510218695).

142171530656073 is an equidigital number, since it uses as much as digits as its factorization.

142171530656073 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47390510218694.

The product of its (nonzero) digits is 3175200, while the sum is 51.

The spelling of 142171530656073 in words is "one hundred forty-two trillion, one hundred seventy-one billion, five hundred thirty million, six hundred fifty-six thousand, seventy-three".