Base | Representation |
---|---|
bin | 11010011110110101… |
… | …00000011011111001 |
3 | 1100200211021011022022 |
4 | 31033122200123321 |
5 | 213104104004203 |
6 | 10310433004225 |
7 | 1012213431032 |
oct | 151732403371 |
9 | 40624234268 |
10 | 14217250553 |
11 | 60362a3850 |
12 | 29093b3675 |
13 | 1457625cbc |
14 | 98c2a9a89 |
15 | 583248a38 |
hex | 34f6a06f9 |
14217250553 has 4 divisors (see below), whose sum is σ = 15509727888. Its totient is φ = 12924773220.
The previous prime is 14217250511. The next prime is 14217250627. The reversal of 14217250553 is 35505271241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14217250553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14217250753) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 646238651 + ... + 646238672.
It is an arithmetic number, because the mean of its divisors is an integer number (3877431972).
Almost surely, 214217250553 is an apocalyptic number.
It is an amenable number.
14217250553 is a deficient number, since it is larger than the sum of its proper divisors (1292477335).
14217250553 is a wasteful number, since it uses less digits than its factorization.
14217250553 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1292477334.
The product of its (nonzero) digits is 42000, while the sum is 35.
The spelling of 14217250553 in words is "fourteen billion, two hundred seventeen million, two hundred fifty thousand, five hundred fifty-three".
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