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14220134304251 is a prime number
BaseRepresentation
bin1100111011101110001000…
…0011011100100111111011
31212100102122121110021022012
43032323202003130213323
53330440313340214001
650124350045120135
72665241120150051
oct316734203344773
955312577407265
1014220134304251
1145927a8107657
121717b5a25904b
137c1c50712705
143723885d61d1
15199d71cbc2bb
hexceee20dc9fb

14220134304251 has 2 divisors, whose sum is σ = 14220134304252. Its totient is φ = 14220134304250.

The previous prime is 14220134304247. The next prime is 14220134304353. The reversal of 14220134304251 is 15240343102241.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14220134304251 - 22 = 14220134304247 is a prime.

It is a super-3 number, since 3×142201343042513 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (14220134304221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7110067152125 + 7110067152126.

It is an arithmetic number, because the mean of its divisors is an integer number (7110067152126).

Almost surely, 214220134304251 is an apocalyptic number.

14220134304251 is a deficient number, since it is larger than the sum of its proper divisors (1).

14220134304251 is an equidigital number, since it uses as much as digits as its factorization.

14220134304251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 14220134304251 its reverse (15240343102241), we get a palindrome (29460477406492).

The spelling of 14220134304251 in words is "fourteen trillion, two hundred twenty billion, one hundred thirty-four million, three hundred four thousand, two hundred fifty-one".