Base | Representation |
---|---|
bin | 1100111011101110001000… |
… | …0011011100100111110111 |
3 | 1212100102122121110021022001 |
4 | 3032323202003130213313 |
5 | 3330440313340213442 |
6 | 50124350045120131 |
7 | 2665241120150044 |
oct | 316734203344767 |
9 | 55312577407261 |
10 | 14220134304247 |
11 | 45927a8107653 |
12 | 1717b5a259047 |
13 | 7c1c50712701 |
14 | 3723885d61cb |
15 | 199d71cbc2b7 |
hex | ceee20dc9f7 |
14220134304247 has 2 divisors, whose sum is σ = 14220134304248. Its totient is φ = 14220134304246.
The previous prime is 14220134304221. The next prime is 14220134304251. The reversal of 14220134304247 is 74240343102241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14220134304247 - 219 = 14220133779959 is a prime.
It is a super-3 number, since 3×142201343042473 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14220134304547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7110067152123 + 7110067152124.
It is an arithmetic number, because the mean of its divisors is an integer number (7110067152124).
Almost surely, 214220134304247 is an apocalyptic number.
14220134304247 is a deficient number, since it is larger than the sum of its proper divisors (1).
14220134304247 is an equidigital number, since it uses as much as digits as its factorization.
14220134304247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129024, while the sum is 37.
Adding to 14220134304247 its reverse (74240343102241), we get a palindrome (88460477406488).
The spelling of 14220134304247 in words is "fourteen trillion, two hundred twenty billion, one hundred thirty-four million, three hundred four thousand, two hundred forty-seven".
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