142204044142331 has 2 divisors, whose sum is σ = 142204044142332. Its totient is φ = 142204044142330.

The previous prime is 142204044142313. The next prime is 142204044142333. The reversal of 142204044142331 is 133241440402241.

Together with previous prime (142204044142313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142204044142331 is a prime.

It is a super-2 number, since 2×142204044142331² (a number of 29 digits) contains 22 as substring.

Together with 142204044142333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 142204044142291 and 142204044142300.

It is not a weakly prime, because it can be changed into another prime (142204044142333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71102022071165 + 71102022071166.

It is an arithmetic number, because the mean of its divisors is an integer number (71102022071166).

Almost surely, 2^{142204044142331} is an apocalyptic number.

142204044142331 is a deficient number, since it is larger than the sum of its proper divisors (1).

142204044142331 is an equidigital number, since it uses as much as digits as its factorization.

142204044142331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 73728, while the sum is 35.

Adding to 142204044142331 its reverse (133241440402241), we get a palindrome (275445484544572).

The spelling of 142204044142331 in words is "one hundred forty-two trillion, two hundred four billion, forty-four million, one hundred forty-two thousand, three hundred thirty-one".