142211145521 has 2 divisors, whose sum is σ = 142211145522. Its totient is φ = 142211145520.

The previous prime is 142211145481. The next prime is 142211145523. The reversal of 142211145521 is 125541112241.

142211145521 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 137540106496 + 4671039025 = 370864^2 + 68345^2 .

It is an emirp because it is prime and its reverse (125541112241) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142211145521 is a prime.

It is a super-2 number, since 2×142211145521² (a number of 23 digits) contains 22 as substring.

Together with 142211145523, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (142211145523) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71105572760 + 71105572761.

It is an arithmetic number, because the mean of its divisors is an integer number (71105572761).

Almost surely, 2^142211145521 is an apocalyptic number.

It is an amenable number.

142211145521 is a deficient number, since it is larger than the sum of its proper divisors (1).

142211145521 is an equidigital number, since it uses as much as digits as its factorization.

142211145521 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3200, while the sum is 29.

Adding to 142211145521 its reverse (125541112241), we get a palindrome (267752257762).

The spelling of 142211145521 in words is "one hundred forty-two billion, two hundred eleven million, one hundred forty-five thousand, five hundred twenty-one".