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1422123136453 = 12469911404447
BaseRepresentation
bin10100101100011101001…
…001001111010111000101
312000221202012120120102001
4110230131021033113011
5141300002010331303
63005151522145301
7204513352132105
oct24543511172705
95027665516361
101422123136453
114a9134488138
121ab74a1b2231
13a414b110566
144cb8c881205
1526ed54b331d
hex14b1d24f5c5

1422123136453 has 4 divisors (see below), whose sum is σ = 1422134665600. Its totient is φ = 1422111607308.

The previous prime is 1422123136417. The next prime is 1422123136457. The reversal of 1422123136453 is 3546313212241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1422123136453 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1422123136457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5577525 + ... + 5826922.

It is an arithmetic number, because the mean of its divisors is an integer number (355533666400).

Almost surely, 21422123136453 is an apocalyptic number.

It is an amenable number.

1422123136453 is a deficient number, since it is larger than the sum of its proper divisors (11529147).

1422123136453 is a wasteful number, since it uses less digits than its factorization.

1422123136453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11529146.

The product of its digits is 103680, while the sum is 37.

Adding to 1422123136453 its reverse (3546313212241), we get a palindrome (4968436348694).

The spelling of 1422123136453 in words is "one trillion, four hundred twenty-two billion, one hundred twenty-three million, one hundred thirty-six thousand, four hundred fifty-three".

Divisors: 1 124699 11404447 1422123136453