14222433241451 has 2 divisors, whose sum is σ = 14222433241452. Its totient is φ = 14222433241450.

The previous prime is 14222433241441. The next prime is 14222433241453. The reversal of 14222433241451 is 15414233422241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14222433241451 - 2³⁴ = 14205253372267 is a prime.

Together with 14222433241453, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14222433241453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111216620725 + 7111216620726.

It is an arithmetic number, because the mean of its divisors is an integer number (7111216620726).

Almost surely, 2^{14222433241451} is an apocalyptic number.

14222433241451 is a deficient number, since it is larger than the sum of its proper divisors (1).

14222433241451 is an equidigital number, since it uses as much as digits as its factorization.

14222433241451 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 184320, while the sum is 38.

Adding to 14222433241451 its reverse (15414233422241), we get a palindrome (29636666663692).

The spelling of 14222433241451 in words is "fourteen trillion, two hundred twenty-two billion, four hundred thirty-three million, two hundred forty-one thousand, four hundred fifty-one".