Base | Representation |
---|---|
bin | 1100111011111000110011… |
… | …0111010010100100110011 |
3 | 1212100201001022210210001122 |
4 | 3032332030313102210303 |
5 | 3331012201001140144 |
6 | 50125542255252455 |
7 | 2665402125303206 |
oct | 316761467224463 |
9 | 55321038723048 |
10 | 14223000021299 |
11 | 4593a387a0253 |
12 | 1718619b1a12b |
13 | 7c22b933bb84 |
14 | 37257b04593d |
15 | 199e8d6887ee |
hex | cef8cdd2933 |
14223000021299 has 2 divisors, whose sum is σ = 14223000021300. Its totient is φ = 14223000021298.
The previous prime is 14223000021283. The next prime is 14223000021301. The reversal of 14223000021299 is 99212000032241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14223000021299 - 24 = 14223000021283 is a prime.
Together with 14223000021301, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14223000021259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111500010649 + 7111500010650.
It is an arithmetic number, because the mean of its divisors is an integer number (7111500010650).
Almost surely, 214223000021299 is an apocalyptic number.
14223000021299 is a deficient number, since it is larger than the sum of its proper divisors (1).
14223000021299 is an equidigital number, since it uses as much as digits as its factorization.
14223000021299 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 14223000021299 in words is "fourteen trillion, two hundred twenty-three billion, twenty-one thousand, two hundred ninety-nine".
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