142230134332001 has 2 divisors, whose sum is σ = 142230134332002. Its totient is φ = 142230134332000.

The previous prime is 142230134331979. The next prime is 142230134332003. The reversal of 142230134332001 is 100233431032241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 142230072300625 + 62031376 = 11926025^2 + 7876^2 .

It is a cyclic number.

It is not a de Polignac number, because 142230134332001 - 2²⁶ = 142230067223137 is a prime.

It is a super-2 number, since 2×142230134332001² (a number of 29 digits) contains 22 as substring.

Together with 142230134332003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (142230134332003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71115067166000 + 71115067166001.

It is an arithmetic number, because the mean of its divisors is an integer number (71115067166001).

Almost surely, 2^{142230134332001} is an apocalyptic number.

It is an amenable number.

142230134332001 is a deficient number, since it is larger than the sum of its proper divisors (1).

142230134332001 is an equidigital number, since it uses as much as digits as its factorization.

142230134332001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 142230134332001 its reverse (100233431032241), we get a palindrome (242463565364242).

The spelling of 142230134332001 in words is "one hundred forty-two trillion, two hundred thirty billion, one hundred thirty-four million, three hundred thirty-two thousand, one".