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14223041030453 is a prime number
BaseRepresentation
bin1100111011111000111101…
…0011101110100100110101
31212100201011011222021001012
43032332033103232210311
53331012242000433303
650125550322242005
72665403134003343
oct316761723564465
955321134867035
1014223041030453
114593a59960012
12171862b7b6305
137c22c4999b48
1437258267c993
15199e920895d8
hexcef8f4ee935

14223041030453 has 2 divisors, whose sum is σ = 14223041030454. Its totient is φ = 14223041030452.

The previous prime is 14223041030431. The next prime is 14223041030461. The reversal of 14223041030453 is 35403014032241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13718852986609 + 504188043844 = 3703897^2 + 710062^2 .

It is an emirp because it is prime and its reverse (35403014032241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14223041030453 - 26 = 14223041030389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14223041030353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111520515226 + 7111520515227.

It is an arithmetic number, because the mean of its divisors is an integer number (7111520515227).

Almost surely, 214223041030453 is an apocalyptic number.

It is an amenable number.

14223041030453 is a deficient number, since it is larger than the sum of its proper divisors (1).

14223041030453 is an equidigital number, since it uses as much as digits as its factorization.

14223041030453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 14223041030453 its reverse (35403014032241), we get a palindrome (49626055062694).

The spelling of 14223041030453 in words is "fourteen trillion, two hundred twenty-three billion, forty-one million, thirty thousand, four hundred fifty-three".