Search a number
-
+
14223044038241 is a prime number
BaseRepresentation
bin1100111011111000111101…
…1111001100111001100001
31212100201011101122001221202
43032332033133030321201
53331012243233210431
650125550510530545
72665403201401403
oct316761737147141
955321141561852
1014223044038241
114593a60624895
121718630806a55
137c22c54b0bbc
14372582c22b73
15199e924808cb
hexcef8f7cce61

14223044038241 has 2 divisors, whose sum is σ = 14223044038242. Its totient is φ = 14223044038240.

The previous prime is 14223044038237. The next prime is 14223044038279. The reversal of 14223044038241 is 14283044032241.

It is an a-pointer prime, because the next prime (14223044038279) can be obtained adding 14223044038241 to its sum of digits (38).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10943790259600 + 3279253778641 = 3308140^2 + 1810871^2 .

It is a cyclic number.

It is not a de Polignac number, because 14223044038241 - 22 = 14223044038237 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14223044038195 and 14223044038204.

It is not a weakly prime, because it can be changed into another prime (14223044038201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111522019120 + 7111522019121.

It is an arithmetic number, because the mean of its divisors is an integer number (7111522019121).

Almost surely, 214223044038241 is an apocalyptic number.

It is an amenable number.

14223044038241 is a deficient number, since it is larger than the sum of its proper divisors (1).

14223044038241 is an equidigital number, since it uses as much as digits as its factorization.

14223044038241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 147456, while the sum is 38.

The spelling of 14223044038241 in words is "fourteen trillion, two hundred twenty-three billion, forty-four million, thirty-eight thousand, two hundred forty-one".