Base | Representation |
---|---|
bin | 1000010001110110100… |
… | …0101011010010101010 |
3 | 111121010022221200021121 |
4 | 2010131220223102222 |
5 | 4312242131414424 |
6 | 145201242325454 |
7 | 13163422412263 |
oct | 2043550532252 |
9 | 447108850247 |
10 | 142231123114 |
11 | 55357840a43 |
12 | 23694ab988a |
13 | 10548b9c8a2 |
14 | 6c53a8b96a |
15 | 3a76a39ee4 |
hex | 211da2b4aa |
142231123114 has 4 divisors (see below), whose sum is σ = 213346684674. Its totient is φ = 71115561556.
The previous prime is 142231123057. The next prime is 142231123127. The reversal of 142231123114 is 411321132241.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 411321132241 = 61 ⋅6742969381.
It can be written as a sum of positive squares in only one way, i.e., 86550698025 + 55680425089 = 294195^2 + 235967^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35557780777 + ... + 35557780780.
Almost surely, 2142231123114 is an apocalyptic number.
142231123114 is a deficient number, since it is larger than the sum of its proper divisors (71115561560).
142231123114 is an equidigital number, since it uses as much as digits as its factorization.
142231123114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71115561559.
The product of its digits is 1152, while the sum is 25.
Adding to 142231123114 its reverse (411321132241), we get a palindrome (553552255355).
The spelling of 142231123114 in words is "one hundred forty-two billion, two hundred thirty-one million, one hundred twenty-three thousand, one hundred fourteen".
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