Base | Representation |
---|---|
bin | 1100111011111001100101… |
… | …1101101100001100011101 |
3 | 1212100201121001120122202002 |
4 | 3032332121131230030131 |
5 | 3331013114110224201 |
6 | 50130015250212045 |
7 | 2665410303151301 |
oct | 316763135541435 |
9 | 55321531518662 |
10 | 14223211414301 |
11 | 4594037054a0a |
12 | 1718678884025 |
13 | 7c2321084aa6 |
14 | 37259b151d01 |
15 | 199ea1ee376b |
hex | cef9976c31d |
14223211414301 has 2 divisors, whose sum is σ = 14223211414302. Its totient is φ = 14223211414300.
The previous prime is 14223211414267. The next prime is 14223211414327. The reversal of 14223211414301 is 10341411232241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13660223808676 + 562987605625 = 3695974^2 + 750325^2 .
It is a cyclic number.
It is not a de Polignac number, because 14223211414301 - 234 = 14206031545117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14223211414381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111605707150 + 7111605707151.
It is an arithmetic number, because the mean of its divisors is an integer number (7111605707151).
Almost surely, 214223211414301 is an apocalyptic number.
It is an amenable number.
14223211414301 is a deficient number, since it is larger than the sum of its proper divisors (1).
14223211414301 is an equidigital number, since it uses as much as digits as its factorization.
14223211414301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 14223211414301 its reverse (10341411232241), we get a palindrome (24564622646542).
The spelling of 14223211414301 in words is "fourteen trillion, two hundred twenty-three billion, two hundred eleven million, four hundred fourteen thousand, three hundred one".
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