Base | Representation |
---|---|
bin | 1100111011111001100110… |
… | …0000110110100101100110 |
3 | 1212100201121010010202220211 |
4 | 3032332121200312211212 |
5 | 3331013114313241202 |
6 | 50130015320050034 |
7 | 2665410313203226 |
oct | 316763140664546 |
9 | 55321533122824 |
10 | 14223212243302 |
11 | 4594037570837 |
12 | 171867900391a |
13 | 7c23212b521a |
14 | 37259b2ca086 |
15 | 199ea21091d7 |
hex | cef99836966 |
14223212243302 has 4 divisors (see below), whose sum is σ = 21334818364956. Its totient is φ = 7111606121650.
The previous prime is 14223212243263. The next prime is 14223212243351. The reversal of 14223212243302 is 20334221232241.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×142232122433022 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3555803060824 + ... + 3555803060827.
It is an arithmetic number, because the mean of its divisors is an integer number (5333704591239).
Almost surely, 214223212243302 is an apocalyptic number.
14223212243302 is a deficient number, since it is larger than the sum of its proper divisors (7111606121654).
14223212243302 is an equidigital number, since it uses as much as digits as its factorization.
14223212243302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7111606121653.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 14223212243302 its reverse (20334221232241), we get a palindrome (34557433475543).
The spelling of 14223212243302 in words is "fourteen trillion, two hundred twenty-three billion, two hundred twelve million, two hundred forty-three thousand, three hundred two".
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